At Rice we asked for C!=RE and C!=Empty set assuming that emty set **not** in C to prove that L={<M>|L(M) in c} is not in R.

what happens if the empty set does belong to C? is it shows a stronger proof - that L is not in RE ? if so why ?

Rice Th

- Instructors
- Prof. Nachum Dershowitz

Prof. Yishay Mansour - Assistants
- Ori Lahav

Mariano Schain

- Exam: Jul. 3
^{rd} - Moed B: Sep. 6
^{th}

**Exam moed B**

(11 Sep 2011 17:01)

**Exam**

(21 Jul 2011 07:22)

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